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3 years ago

Please help me I will give you extra points and the brain thing please help me

Mathematics

1 answer:

9966 [12]3 years ago

4 0

Answer:

A) 32

Step-by-step explanation:

f(x) = 2x² - 24x

If f(x) = 1280, then 2x² - 24x = 1280

Subtract 1280 from both side ⇒ 2x² - 24x - 1280 = 0

Divide both sides by 2 ⇒ x² - 12x - 640 = 0

Factorise ⇒ (x - 32)(x + 20) = 0

Solve ⇒ x = 32 or -20

Therefore, x = 32 (as x ≥ 0)

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3a^4(2b^6c^3)^2 Can someone help me simplify this?

Grace [21]

First you do 3a^4(2b^6c^3)^2
=12a^4b^12c^6

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3 years ago

6w+3+9-2n use w=3 and n=2

Readme [11.4K]

Answer:

Step-by-step explanation:

from what I got lol , your welcome and have a nice day

3 0

3 years ago

Please help out with this QUestion thank chu very much

galina1969 [7]

Answer:

The graph in the attached figure

The point (-1,4) represent a solution

Step-by-step explanation:

we have

$x> -2$ ----> inequality A

$y\leq 2x+7$ ----> inequality B

using a graphing tool

The solution is the shaded area

see the attached figure

Remember that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution of the system of inequalities

The point (-1,4) represent a solution

4 0

4 years ago

Read 2 more answers

What’s the answer ?

andre [41]

Answer:

a ) cylinder

b) triangular pyramid

6 0

2 years ago

1.what is the length of the segment joining 3,6 and -2,-6

OLga [1]

1.what is the length of the segment joining 3,6 and -2,-6 : 13 units

2.what is the center of the circle (x+6)^2+(y-8)^2=144 => (-6,8)

3.what is the slope of the line 3y+2x-6=0=> -2/3

Step-by-step explanation:

1.what is the length of the segment joining (3,6) and (-2,-6)?

Let

(x1,y1) = (3,6)

(x2,y2) = (-2,-6)

The length of a segment is given by:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Putting\ values\\d = \sqrt{(-2-3)^2+(-6-6)^2}\\d = \sqrt{(-5)^2+(-12)^2}\\= \sqrt{25+144}\\= \sqrt{169}\\=13\ units$

2.what is the center of the circle (x+6)^2+(y-8)^2=144

The equation of circle is given by:

$(x-h)^2+(y-k)^2 = r^2$

Here, h and k are the coordinates of centre of circle

x - h = x+6

-h = 6

h = -6

y - 8 = y - k

-8 = - k

k = 8

So,

The center of circle is: (-6,8)

3.what is the slope of the line 3y+2x-6=0

We have to convert the equation in slope-intercept form to find the slope

Slope-intercept form is:

y = mx+b

Now,

$3y+2x-6=0\\3y+2x = 6\\3y = -2x+6$

Dividing both sides by 3

$\frac{3y}{3} = -\frac{2}{3}x+\frac{6}{3}\\y = -\frac{2}{3}x + 2$

In slope-intercept form, the co-efficient of x is the slope of the line so

m = -2/3

Keywords: Coordinate geometry, Slope

Learn more about coordinate geometry at:

#LearnwithBrainly

4 0

3 years ago