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2 years ago

9

A man buys 6 ½ of petrol daily. How many litres of petrol does he purchase in six days

1 answer:

nalin [4]2 years ago

6 0

Answer:

39 liters

Step-by-step explanation:

6.5×6=39

so 39 litres

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Solve each equation.<br> e. log:(6x – 3) = 2

Ipatiy [6.2K]

Answer:

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Step-by-step explanation:

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3 years ago

Identify the slope of the line for the equation y= -2/3× + 1/3

natita [175]

Answer:

$\textbf{The slope of the parallel line is given by $ \frac{-2}{3} $}\\$

Step-by-step explanation:

$\textup{The slope of any two parallel lines are equal and they only differ in their $y- intercepts$. }\\\textup{Given $y = \frac{-2}{3}x + \frac{1}{3} $}\\\textup{This is comparable to $y = mx + c$, where $m$ is the slope of that line.}\\\textup{Therefore, the slope of the given line and any line parallel to it is $ \frac{-2}{3}$.}$

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3 years ago

The perimeter of the triangle shown on the right is 257 feet.

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2 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

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3 years ago

You have two exponential functions. One function has the formula g(x) = 5 x . The other function has the formula h(x) = 5-x . Wh

Marrrta [24]

Hmm it would be k(x)=2(5x) or it could be k(x)=10x

Hope this helps!

5 0

3 years ago

Read 2 more answers