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Bad White [126]
3 years ago
8

The average body temperature of all healthy adults is 98.6 F. A doctor takes a random sample of 100 healthy adults and records t

he temperature of each. The average temperature of these 100 adults is 98.2 F and the standard deviation is 6.9 F. Identify the values of the statistic and the parameter(s).
Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Explained below.

Step-by-step explanation:

A parameter is a valuable element of statistical analysis. It denotes the characteristics that are used to define a given population. It is used to define a particular attribute of the population. For instance, population mean, population standard deviation, population proportion and so on.

  • The parameter of interest is the average body temperature of all healthy adults, <em>μ</em> = 98.6°F.

While making a statistical conclusion about the population under study, the parameter value is unknown. This is because it would not be possible to gather data from every single member of the population. So a sample is selected from the population to derive a conclusion about the parameter.

A statistic is the value of the characteristics that are computed using this sample. For instance, sample mean, sample standard deviation, sample proportion and so on.

  • The statistic is the average body temperature of 100 randoly selected healthy adults, \bar x=98.2^{o}F.
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A, C, D

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3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu
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Answer:

Probability distribution for x:

P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

So, we have this probabilty distribution for x:

P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\

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3 years ago
The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi
aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

<u>GIVEN :-</u>

  • First term of G.P. = 6
  • Forth term of G.P. = 384

<u>TO FIND :-</u>

  • Sum of first 10 terms of the G.P.

<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>

<em>Geometric Progression :-</em>

  • It's a sequence in which the successive terms have same ratio.
  • General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
  • Sum of 'n' terms of a G.P. ⇒ \frac{a(r^n - 1)}{r-1}.

<em>[NOTE :- </em>\frac{a(1-r^n)}{1-r} can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator &  denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>

<u>SOLUTION :-</u>

Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.

⇒ a = 6

It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-

=> ar^3 = 384

=> 6r^3 = 384

Divide both the sides by 6.

=> \frac{6r^3}{6} = \frac{384}{6}

=> r^3 = 64

=> r = \sqrt[3]{64} = 4

Sum of first 10 terms = \frac{6(4^{10}-1)}{4 - 1}

                                     = \frac{6(1048576 - 1)}{3}

                                     = 2 \times 1048575

                                     = 2097150

6 0
3 years ago
Does (6, 3) make the equation y = 2x true​
katrin [286]

Answer:

no

Step-by-step explanation:

y = 2x

Substitute the points into the equation

3 = 2(6)

3 = 12

This is false

The point does not make the equation true

8 0
3 years ago
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