Assume that a fair six-sided die is rolled 13 times, and the roll is called a success if the result is in {1,2,3,4}. What is the
1 answer:
Answer:
The answer to the question is;
The probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls is .
Step-by-step explanation:
The probability of success = 1/2 =
probability of failure = 1/2
Since we have 4 success we then have 9 failures and the given probability can be solved as ₁₃C₄ × 1/2ⁿ×1/2¹³⁻ⁿ
Therefore we have
₁₃C₄ × 1/2⁴×1/2⁹ = 715/8192
That is the probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls = 715/8192.
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Number of Men, n(M)=24
Number of Women, n(W)=3
Total Sample, n(S)=24+3=27
Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>
(a)Probability that both appointees are men.
(b)Probability that one man and one woman are appointed.
To find the probability that one man and one woman are appointed, this could happen in two ways.
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(c)Probability that at least one woman is appointed.
The probability that at least one woman is appointed can occur in three ways.
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- A woman is appointed first and a man is appointed next.
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In Part B,
Therefore:
Answer:
-85
Explanation:
Given the mathematical expression:
First, we recall the product of signs.
So, first, we open the bracket:
We then simplify:
The result is -85.