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storchak [24]
3 years ago
10

Assume that a fair six-sided die is rolled 13 times, and the roll is called a success if the result is in {1,2,3,4}. What is the

probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls?
Mathematics
1 answer:
Deffense [45]3 years ago
5 0

Answer:

The answer to the question is;

The probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls is \frac{715}{8192}.

Step-by-step explanation:

The probability of success = 1/2 =

probability of failure  = 1/2

Since we have 4 success we then have 9 failures and the given probability can be solved as ₁₃C₄ × 1/2ⁿ×1/2¹³⁻ⁿ

Therefore  we have

₁₃C₄ × 1/2⁴×1/2⁹ =  715/8192

That is the probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls = 715/8192.

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Answer:

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Step-by-step explanation:

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3 years ago
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forsale [732]
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Now that we know the value of one variable, we can take that value and plug it back into one of the original equations and solve for the value of the other variable.

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