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gulaghasi [49]
2 years ago
10

May anyone help me i have no idea

Mathematics
1 answer:
shtirl [24]2 years ago
7 0

Answer:

No.  GCF = 2

2(x^2 - 5x + 10)

2(x^2 - 5x + 10)       (\dfrac{-5}{2})^2=(-2.5)^2 =6.25

2[x^2 - 5x+6.25-6.25 + 10]

2[(x^2 - 5x+6.25)-6.25 + 10]

2[(x - 2.5)^2-6.25+ 10]

2[(x - 2.5)^2+3.75]

2(x - 2.5)^2+7.5

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There are 50 pages in a chapter. Claire read 17 pages of the chapter on Sunday.
nexus9112 [7]

Answer:

She read 34% of the chapter

Step-by-step explanation:

You divide 17 by 50 and that gives you your answer

17/50=.34

move the decimal point 2 places to the right and the gives you your precent

.34=34%

5 0
2 years ago
(04.01)
katrin [286]
The third one, 2 to the power of 5 over 6

√2  * 3√2

convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )

2^(1/2) * 2^(1/3)  
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2)  - convert back to radical form 
6√(2^3 * 2^2)- combine

6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~

5 0
3 years ago
MATHEMATICS
Over [174]

Answer:

1 .i think it is d

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it
Zanzabum

Answer:

\beta=45\degree\:\:or\:\:\beta=135\degree

Step-by-step explanation:

We want to solve \tan \beta \sec \beta=\sqrt{2}, where 0\le \beta \le360\degree.

We rewrite in terms of sine and cosine.

\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}

\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}

Use the Pythagorean identity: \cos^2\beta=1-\sin^2\beta.

\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}

\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)

\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta

\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0

This is a quadratic equation in \sin \beta.

By the quadratic formula, we have:

\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }

\sin \beta=\frac{2}{2\cdot \sqrt{2} } or \sin \beta=\frac{-4}{2\cdot \sqrt{2} }

\sin \beta=\frac{1}{\sqrt{2} } or \sin \beta=-\frac{2}{\sqrt{2} }

\sin \beta=\frac{\sqrt{2}}{2} or \sin \beta=-\sqrt{2}

When \sin \beta=\frac{\sqrt{2}}{2} , \beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )

\implies \beta=45\degree\:\:or\:\:\beta=135\degree on the interval 0\le \beta \le360\degree.

When  \sin \beta=-\sqrt{2}, \beta is not defined because -1\le \sin \beta \le1

4 0
3 years ago
What is the value of 100?
Nesterboy [21]

Answer:

10

Step-by-step explanation:

Means back the numbers into multiples of several small numbers

Like:; 1. We take LCM of 40

Just break into multiples of small number

40= 2×2×2×5

2. We take LCM of 50

50= 5×5×2

So LCM for 100 is 2×2×5×5

after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)

Then write the the single number in place of two multipled numbers

Like:; 2×2 is written as 2 // 3×3 is written as 3

So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)

write pairs in single number 2×5

And so we get 2×5=10

So we find root of 100 that is 10

8 0
3 years ago
Read 2 more answers
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