★ QUADRATIC RESOLUTION ★
Roots of the given equation will be imaginary because it's discriminant is less than 0 and hence it'll yield imaginary solutions
D < 0
b² - 4ac < 0
4² - 4 ( 5 ) < 0
16 - 20 < 0
-4 < 0
Hence it's character is stated above
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Answer:
Step-by-step explanation:
Y = kxz
Putting values of y x and z in the equation
4 = k(2)(3)
4 = k6
2/3 = k
Now finding y when x = - 6 and z = 2
Y = kxz
= 2/3(-6)(2)
= - 8
Circle equation: (x - h) + (x - k) = r²
(h, k) = center
r = radius
The center is (-7, 4)
To find the radius, take the square root of 49.
√49 = 7
The radius is 7.
Best of Luck!
If he has 484 plants and there are as many rows as there are plants in each row, his field is a square.
The area of a square = (side)^2
In this problem,
Area = 484
side = # of rows
Let's plug our values into the formula above
484 plants = (side)^2
Take the sqrt of both sides.
22 rows = side.
ANSWER:
STEP-BY-STEP EXPLANATION: