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2 years ago

12

Given that cos a equals 4/5 what is sin a/2

1 answer:

astra-53 [7]2 years ago

8 0

-0.31622... yeah i think it is that

You might be interested in

Х<br> Find the measure of ZXYZ.

sergiy2304 [10]

Answer:

150 Degrees

Step-by-step explanation:

Each color strip represents 10 degrees since a circle is 360 degrees, and there are 36 strips. Since inside of the angle there are 15 strips that means that the angle is 150 degrees.

Hope that helps!

MARK BRAINLIEST!

8 0

2 years ago

27 is what percent of 150?

wlad13 [49]

18%

27/150 = 0.18

multiply by 100

0.18 * 100 = 18%

8 0

3 years ago

Read 2 more answers

You work in a chemical lab. Last quarter, you successfully completed an average of about 5 chemical analyses per day. This quart

Kryger [21]

Answer: 60%

Step-by-step explanation:

Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.

Therefore initially our average = 5 chemical analyses per day.

Again, From the question, This quarter, we have increased this average to about 8 per day.

Therefore New average =chemical analyses 8 per day

Thus, Percentage change in the average = (Initial average - New average)×100/ initial average

= $\frac{8-5}{5} \times 100$

= $\frac{3}{5} \times 100$

= 60 %

Therefore, Percentage change in the average=60 %

7 0

2 years ago

Read 2 more answers

At what time the sum Rs. 5000 will be doubled at the interest<br>of 10% per annum?

FromTheMoon [43]

Answer:

Time= $10$ years

Step-by-step explanation:

Let total time $=t$

Initial Amount $=5000$

Final Amount $=10000$

Total interest = Final Amount - Initial Amount

$=10000-5000\\=5000$

Simple Interest $=\frac{Initial Amount\times time\times rate}{100} \\\\5000=\frac{5000\times t \times 10}{100}\\\frac{t}{10} =1\\t=10 \ years$

7 0

3 years ago

Determine if the given mapping phi is a homomorphism on the given groups. If so, identify its kernel and whether or not the mapp

shtirl [24]

Answer:

(a) No. (b)Yes. (c)Yes. (d)Yes.

Step-by-step explanation:

(a) If $\phi: G \longrightarrow G$ is an homomorphism, then it must hold

that $b^{-1}a^{-1}=(ab)^{-1}=\phi(ab)=\phi(a)\phi(b)=a^{-1}b^{-1}$ ,

but the last statement is true if and only if G is abelian.

(b) Since G is abelian, it holds that

$\phi(a)\phi(b)=a^nb^n=(ab)^{n}=\phi(ab)$

which tells us that $\phi$ is a homorphism. The kernel of $\phi$

is the set of elements g in G such that $g^{n}=1$ . However,

$\phi$ is not necessarily 1-1 or onto, if $G=\mathbb{Z}_6$ and

n=3, we have

$kern(\phi)=\{0,2,4\} \quad \text{and} \quad\\\\Im(\phi)=\{0,3\}$

(c) If $z_1,z_2 \in \mathbb{C}^{\times}$ remeber that

$|z_1 \cdot z_2|=|z_1|\cdot|z_2|$ , which tells us that $\phi$ is a

homomorphism. In this case

$kern(\phi)=\{\quad z\in\mathbb{C} \quad | \quad |z|=1 \}$ , if we write a

complex number as $z=x+iy$ , then $|z|=x^2+y^2$ , which tells

us that $kern(\phi)$ is the unit circle. Moreover, since

$kern(\phi) \neq \{1\}$ the mapping is not 1-1, also if we take a negative

real number, it is not in the image of $\phi$ , which tells us that

$\phi$ is not surjective.

(d) Remember that $e^{ix}=\cos(x)+i\sin(x)$ , using this, it holds that

$\phi(x+y)=e^{i(x+y)}=e^{ix}e^{iy}=\phi(x)\phi(x)$

which tells us that $\phi$ is a homomorphism. By computing we see

that $kern(\phi)=\{2 \pi n| \quad n \in \mathbb{Z} \}$ and

$Im(\phi)$ is the unit circle, hence $\phi$ is neither injective nor

surjective.

7 0

3 years ago