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yKpoI14uk [10]
3 years ago
15

A rope 29 ft long rope is tied to the top of a flag pole. The rope is staked to the ground 21 ft away from the base of the pole.

How tall is the flag pole?
A)
20 ft


B)
28 ft


C)
32 ft


D)
36 ft

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0
THE answer is D i hope it is correct
RSB [31]3 years ago
3 0
The answer is A here I explained it

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Irene además de 4 pantalones y 6 camisetas tiene 3 gorras cuántas indumentarias de pantalón camiseta gorra puede llevar​
Sidana [21]

Answer:

jsjJHzhhzhahahahjsjsjsj hajajsjjsjsjsjjjsjajjajsjzjzjzjsjsjsjjsjsnsjsnjsjsn

3 0
3 years ago
Please help me no links!!
kaheart [24]

Answer:

Slope is -3

y-intercept is -3 and equation is y=-3x-3

6 0
3 years ago
Read 2 more answers
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
Find each measure cause i don't understand?
vekshin1

Answer:

x=6 .  m<PQS=82  m<SQR=61 :)

Step-by-step explanation:

(13x+4) + (10x-1) = 141

combine like terms

23x+3=141

subtract 3 from both sides

23x=138

divide both sides by 23

x=6

substitute x into both original equations

m<PQS=13(6)+4

m<PQS=78+4

m<PQS= 82

m<SQR=10(6)+1

m<SQR=60+1

M<SQR=61

4 0
3 years ago
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Four students were discussing how to find the unit rate for a proportional relationship. Which method is valid?
LenKa [72]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
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