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3 years ago

50 pts help me please

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

Answer:

ITS BBBBBBBBB

Step-by-step explanation:

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Please help quickly, will mark BRAINLIEST!

olga nikolaevna [1]

Answer:

i got .61. im pretty sure its correct. pls mark as brainliest

Step-by-step explanation:

8 0

3 years ago

The school that Stefan goes to is selling tickets to a choral performance on the first day of ticket sales the school sold three

Serggg [28]

The price of 1 senior citizen ticket is $ 8

Solution:

Let "x" be the price of 1 senior citizen ticket

Let "y" be the price of 1 child ticket

The school sold three senior citizen tickets and one child ticket for a total of $38

Therefore, we frame a equation as:

three senior citizen tickets x price of 1 senior citizen ticket + one child ticket x price of 1 child ticket = 38

$3 \times x + 1 \times y = 38$

3x + y = 38 --------- eqn 1

The school took an $52 on the second day by selling three senior citizen tickets and two child tickets

Therefore, we frame a equation as:

three senior citizen tickets x price of 1 senior citizen ticket + two child ticket x price of 1 child ticket = 52

$3 \times x + 2 \times y = 52$

3x + 2y = 52 ---------- eqn 2

Solve eqn 1 and eqn 2

Subtract eqn 1 from eqn 2

3x + 2y - 3x - y = 52 - 38

Substitute y = 14 in eqn 1

3x + y = 38

3x + 14 = 38

3x = 24

Thus the price of 1 senior citizen ticket is $ 8

7 0

3 years ago

When rounded to the hundreds place, which of the numbers below round to 23,400? Select all that apply.

Nadusha1986 [10]

Answer:

a, c, and d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Two particles travel along the space curves r(t) and u(t). A collision will occur at the point of intersection if both particles

svetoff [14.1K]

Answer:

Point of intersection (x, y, z) = (16, 16, 16)

1. a. Yes

2. a. Yes

Step-by-step explanation:

In order for the particles to colide (and therefore have their paths intersect), the values for the i, j, and k coordinates must be equal for a given 't':

For the i coordinate:

$i_{r(t)} =i_{u(t)}\\t^2=3t+4\\t=\frac{3\pm\sqrt{9-4*1*(-4)} }{2}\\t=4\ or\ -1$

For the j coordinate:

$j_{r(t)} =j_{u(t)}\\9t-20=t^2\\t=\frac{9\pm\sqrt{81-4*1*20} }{2}\\t=4\ or\ 5$

For the k coordinate:

$k_{r(t)} =k_{u(t)}\\t^2=5t-4\\t=\frac{5\pm\sqrt{25-4*1*4} }{2}\\t=4\ or\ 1$

As we can see, for t =4, both paths have the same coordinates and therefore they intersect and the particles will colide.

$r(4) = 4^2i + (9*4 - 20)j + 4^2k \\r(4)=16i+16j+16k\\u(4) = (3*4 + 4)i + 4^2j + (5*4 - 4)k\\u(4)=16i+16j+16k$

Point of intersection (x, y, z) = (16, 16, 16)

5 0

4 years ago

Examine the system of equations, Y = -1/4x -2 , x=4 What is the solution

Nina [5.8K]

Answer:

Y = -1/14

Y = -0.0714

Step-by-step explanation:

Y = -1/4x -2 , x=4

Solution:

Y = -1/4x -2 .........equation(a)

put x = 4 in equation(a)

Y = -1/4(4) -2

Y = -1/16 -2

Y = -1/14

Y = -0.0714

7 0

3 years ago