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ladessa [460]
2 years ago
10

The policy of the Black Oyster Pawnshop is to lend up to 30% of the value of a borrower’s collateral. Pete wants to use a $2,000

guitar and a $900 camera as collateral for a loan. What is the maximum amount that he could borrow from Black Oyster?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
4 0

Answer:

$870

8.7×10²

Step-by-step explanation:

0.3×($900+$2,000)

0.3×$2900

=$870

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The cost of having a package delivered has a base fee of $9.70. Every pound over 5 lbs cost an additional $0.46 per pound. Write
FrozenT [24]
The linear model of this case takes the form:

y = a(x-b) + k

<span>The cost of having a package delivered has a base fee of $9.70
this is "k" >>>>>  k=9.7 (fixed amount of fee)

THEN

</span>
<span>Every pound over 5 lbs cost an additional $0.46 per pound

that means: 0.46(x-5)
in other words, if the package weighs foe example 9 pounds, then 9-5=4, it will cost 0.46*4 for these 4 extra pounds

Finally we have the linear form of this: C = 0.46 (W - 5) + 9.7
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3 0
3 years ago
What two fractions are being<br> multiplied?
tiny-mole [99]
I see 2/3 and 1/2 being multiplied
3 0
3 years ago
Three friends go to the movies and spend a total of $75.00. Each friend bought a ticket and a small popcorn that cost $8.25 how
Basile [38]

Answer:

16.75 Dollars for each Ticket

Step-by-step explanation:

They are three friends so the total money they spent is 75 Dollars so a popcorn costs 8.25 EACH friend so

8.25 x 3

= 24.75

24.75 dollars was spent on the 3 popcorns.

Subtract the total money spent and the total money spent on the 3 popcorns so

75. 00 - 24.75

= 50.25

50.25 dollars were totally spent on the tickets but we're looking for each ticket so divide it by 3.

50.25/3

= 16.75

16.75 dollars each were spent on each ticket.

Thank you and pls mark me as brainliest! Love y'all!

7 0
3 years ago
Jane wants to find the area of a trapezoid. To find the area of a trapezoid, add the two bases, multiply by the height, then div
yawa3891 [41]
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3 years ago
The lifetime, in years, of some electronic component is a continuous random variable with the density f(x) =   k x4 for x ≥ 1
yuradex [85]

I suppose the density is supposed to be

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For this to be a proper density function, it must be positive (it is) and its integral over the support [1,\infty) must evaluate to 1. We have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_1^\infty\frac k{x^4}\,\mathrm dx=-\frac k{3x^3}\bigg|_1^\infty=\frac k3=1

which means k=3.

The distribution function is obtained by integrating the density:

F(x)=\displaystyle\int_{-\infty}^xf(t)\,\mathrm dt=\begin{cases}0&\text{for }x

The probability that the component exceeds 2 years in its lifetime is

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3 0
3 years ago
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