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3 years ago

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Jane wants to find the area of a trapezoid. To find the area of a trapezoid, add the two bases, multiply by the height, then div

ide by 2. The bases and height of the trapezoid are shown. Represent the area of the trapezoid with a numerical expression.

1 answer:

yawa3891 [41]3 years ago

8 0

You do not show us, so I can not answer this question.

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3 people equally share 4 oranges. How many oranges does each person get?

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1 1/3 or 4/3 of an orange to each person. Suppose you cut each orange into thirds (1/3 * 4)

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3 years ago

Please help and show how :) i will mark you brainliest please help

levacccp [35]

It is the fourth one because n could be any number on that red line because it’s is greater than -3

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3 years ago

Read 2 more answers

To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t

nikklg [1K]

Answer:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

$p_v =P(t_{(18)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=19.1$ represent the mean for the sample mean for 1

$\bar X_{2}=23.3$ represent the mean for the sample mean for 2

$s_{1}=4.818$ represent the sample standard deviation for the sample 1

$s_{2}=5.559$ represent the sample standard deviation for the sample 2

$n_{1}=10$ sample size selected 1

$n_{2}=10$ sample size selected 2

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \geq \mu_{2}$

Alternative hypothesis: $\mu_{1} < \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=10+10-2=18$

Since is a one sided test the p value would be:

$p_v =P(t_{(18)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

4 0

3 years ago

Please help!! I don't know what to do :(

elena55 [62]

Yo sup??

This question can be solved by applying the properties of similar triangles

the triangle with sides 5x and 20 is similar to the triangle with sides 45 and 36

therefore we can say

5x/45=20/36

x=5 units

Hope this helps

8 0

3 years ago

21. Paul has $900 to invest in a savings account that has an annual interest rate of 1.8%, and a money market account that pays

Iteru [2.4K]

The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

The interest earned after one year is <u>0.018·x</u>

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing <em>x</em> dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

$\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}$

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

$\displaystyle Interest, \ I = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}$

Plugging in the values gives;

$\displaystyle I = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x$

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

$\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}$

Which gives;

$\displaystyle Interest = \frac{x \times 1.8 \times 1}{100} = 0.018 \cdot x$

Interest earned by investing in the savings account for one year, I = 0.018·x

The polynomial representing the interest earned is <u><em>I</em></u><u> = 0.018·x</u>

Learn more here:

brainly.com/question/11314161

4 0

2 years ago