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xenn [34]
3 years ago
6

Plz help due today .

Mathematics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

xcv

Step-by-step explanation:

sd

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Write a problem situation for this inequality 72-12a<24
Morgarella [4.7K]

Answer:

Subtracted 12 times a number from 72 is less than 24.

Step by step solution

Given inequality is 72-12a

We need to write in word.  

12a means 12 times a number “a”

72-12a means subtract 12a from 72.

72-12a<24 means result is less than 24.  

Inequality shows “Subtracted 12 times a number from 72 is less than 24”

If we solve for number “a”

-12a<24-72

-12a<-24

a>2

All the number greater than 2 satisfy the given inequality.  



4 0
3 years ago
What is the surface area if a cube whose edges are 13sqrt(5) cm?
Usimov [2.4K]
By formula of surface area of cube
5 0
3 years ago
Whoever answers first will get brainiest!
Semenov [28]
Possibly I believe 14
8 0
3 years ago
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Can someone please answer this question please answer it correctly and please show work please help me I need it
Murrr4er [49]

Answer:

B

Step-by-step explanation:

Subtracting v - q, will be subtracting the atmosphere to the sun - surface to the sun.

The answer will be negative distance of the atmosphere.

However, we cant really have a 'negative' atmosphere, this is where the |absolute value| signs make this problem correct.

5 0
3 years ago
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A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
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