Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
you find what they both divide by and then divide each one and then you keep doing that until you cant no more
Step-by-step explanation:
1. when x is 0
y will be
4x+2y=10
4(0)+2y=10
0+2y=10
collect like terms
2y=10-0
2y=10
divide both sides by 2
2y/2=10/2
y=5
so when x =0 y will equal to 5
2. when x is 1
y will be
4x+2y=10
4(1)+2y=10
4+2y=10
collect like terms
2y=10-4
2y=6
divide both sides by two
2y/2=6/2
y=3
so when x is 1, y is 3
3. when x is 2
4x+2y=10
4(2)+2y=10
8+2y=10
(CLT) 2y=10-8
2y =2
y= 1
