The answer is -652.39 try that answer
C can be found using pythagoras theorem. c2=a2+b2. Now, b is not given, but we know that cos(theta)=b/c=>b=c*cos(theta). Substituting b in the above relation, c2=a2+c2(cos(theta))^2=>c2=a2/(1-cos((theta))^2). c is the squareroot of c2. Hence c=sqrt(2/(1-cos((theta))^2))
Answer:
No real root.
Complex roots:

Step-by-step explanation:


There are no two integers whose product is 5 and whose sum is 2, so this trinomial is not factorable. We can use the quadratic formula.




Since we have a square root of a negative number, there are no real roots. If you have learned complex numbers, then we can continue.

