Question

16 POINTS HELP ASAP plzzzzzzzzz

Answer 1

Answer:

                            $\large\boxed{\large\boxed{\sqrt{3}$

Explanation:

You are comparing irrational numbers.

By inspection, i.e. at first sight you can only compare $\sqrt{3} \text{ }and\text{ } 2\sqrt{3}$ because they have the same radicand.

You can order: $\sqrt{3}$

You can introduce the 2 inside the radical by squaring it:

       $2\sqrt{3}=\sqrt{2^2\times3}=\sqrt{12}$

Since 5 is between 3 and 12, you can order:

• $\sqrt{3}$

Which is:

• $\sqrt{3}$

You must know that π ≈ 3.14.

5 is less than 9 and the square root of 9 is 3; hence, $\sqrt{5}$ and $\sqrt{5}$

Now you must determine whether π is less than or greater than $\sqrt{12}$

Using a calculator or probing numbers between 3 and 4 you get $\sqrt{12} \approx3.46$

Hence, the complete order is:

•            $\sqrt{3}$