(13 + x)/(50 - x ) = (2/1)
Cross Multiply
2(50-x) = 1(13 + x)
100 - 2x = 13 + x
add 2x to both sides
100 -2x + 2x = 13 + x + 2x
100 = 13 + 3x
Subtract 13 from both sides
100 - 13 = 13 - 13 + 3x
87 = 3x
divide both sides by 3
29 = x
(13 + 29)/(50-29) = 42/21 = 2 to 1 ratio
Answer:6.6 y
Step-by-step explanation:
The answer is x = 4 as it satisfies both inequalities :)
Given: KL is a tangent to the circle.
LM is another tangent to the circle.
We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.
4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5
Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18
Thus, LM = KL = 18 units.
4. 10.
1,2,4 1,2,5,10
2 is the greatest common factor.
