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3 years ago

Need an answer soon!

Mathematics

2 answers:

Tema [17]3 years ago

6 0

Answer:

b < -6

Step-by-step explanation:

-5b + 4(1 + 6b) < -110

-5b + 4 + 24b < -110

-5b + 24b < -110 -4

19b < -144

19b/19 < -144/19

b < -6

Lera25 [3.4K]3 years ago

5 0

−5b+4(1+6b)<−110

Step 1: Simplify both sides of the inequality.

19b+4<−110

Step 2: Subtract 4 from both sides.

19b+4−4<−110−4

19b<−114

Step 3: Divide both sides by 19.

19b/19 < −114/19

answer: b<−6

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Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou

Andru [333]

Answer:

Perimeter of the Quadrilateral=20.78

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Perimeter of the Quadrilateral= AB+BC+CD+AD

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$AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\$

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BC=

$\sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}$

$=3.16$

$CD=\sqrt{(-4-3)^2+(-3-1)^2} \\\\=\sqrt{(-7)^2+(-4)^2} \\\\=\sqrt{49+16}\\\\=\sqrt{65}\\\\ =8.06$

$AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16$

Perimeter of the quadrilateral= AB+BC+CD+AD

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3 years ago

Simplify 7h^2+6h^2+5h^2+6h^2-h^2

iogann1982 [59]

Answer:

23h^2

Step-by-step explanation:

These are all like terms so we add/subtract them from left to right.

7h^2+6h^2+5h^2+6h^2-h^2

= 24h^2 - h^2

= 23h^2 (answer)

6 0

3 years ago