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kumpel [21]
3 years ago
15

How do I solve the rest of this problem?

Mathematics
1 answer:
algol [13]3 years ago
5 0

Answer:

Step-by-step explanation:

continuing from the 3rd line....

10x - 1 = 10x + 8     (subtract 10x from both sides)

10x - 10x - 1 = 10x -10x + 8

-1 = + 8   (this last line is not part of the solution but i'm showing it here so you can see what is going on, obviously -1 cannot be 8)

Since   -1  ≠ 8, the equation has no (i.e zero) solutions

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Point B has coordinates ​(​1,2​). The​ x-coordinate of point A is -8. The distance between point A and point B is 15 units. What
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Answer:

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}} (1)

Where:

l_{AB} - Length of the line segment AB.

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y_{A}, y_{B} - y-coordinates of points A and B.

If we know that l_{AB} = 15, x_{A} = -8, x_{B} = 1 and y_{B} = 2, then the possible coordinates of point A is:

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(2-y_{A})^{2} = 144

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