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kumpel [21]
2 years ago
15

How do I solve the rest of this problem?

Mathematics
1 answer:
algol [13]2 years ago
5 0

Answer:

Step-by-step explanation:

continuing from the 3rd line....

10x - 1 = 10x + 8     (subtract 10x from both sides)

10x - 10x - 1 = 10x -10x + 8

-1 = + 8   (this last line is not part of the solution but i'm showing it here so you can see what is going on, obviously -1 cannot be 8)

Since   -1  ≠ 8, the equation has no (i.e zero) solutions

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John and Jane went to a bakery to get cookies for a party. Jane bought x cookies that were $3 each. John bought x cookies that w
Natasha2012 [34]

Answer:

They spent $15.

Step-by-step explanation:

It's given that Jane bought x cookies, so 3x.

John spent $1 on each of the x cookies he got, and also an extra $10, so x+10.

3x=x+10

2x=10

x=5

So they got 5 cookies each.

5 cookies x $3= $15 (check with $5(1)+$10= $5+$10= $15 )

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2 years ago
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2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

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3 years ago
Dirk plants 12 seedlings in 8 min. At this rate, how many seedlings could he plant in 70 min?
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The answer to this question is B. 105
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I think the answer is 17
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