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2 years ago

Solve for the system of equations put them in order

Mathematics

1 answer:

erastova [34]2 years ago

4 0

Answer:

1. Substitution/Elimination 2. Solve For The Variable 3. Distributive Property 4. Isolate the Variable 5. Combine Like Terms

Step-by-step explanation:

youre welcome

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Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

2 years ago

What decimal is equal to 31/100

BlackZzzverrR [31]

Answer:

0.31

Step-by-step explanation:

So if you divide 31 by 100 all you have to do is move the decimal from right to left the number of zeros you have. Here we have 2 zeros so we move from right to left twice.

0.31

4 0

3 years ago

The sum of 5 consecutive integers is 265. What is the fifth number in this sequence?

son4ous [18]

Five consecutive integers are:

n, n+1, n+2, n+3, n+4 the sum of which is:

5n+10=265 subtract 10 from both sides

5n=255, divide both sides by 5

n=51

Our fifth number was n+4 so the fifth number is 55

3 0

2 years ago

Read 2 more answers

Which of the following is a point-slope equation of a line that passes through

Helen [10]

A

i need to put 20 characters in here so imma tell you, just use desmos.com. if you type in the equations, it’ll show you the graph

6 0

3 years ago

The times required for a delivery firm to transport a package from one business address to another in the same metropolitan area

gladu [14]

Answer:

Step-by-step explanation:

Since; the density function diagrams were not included in the question; we will be unable to determine the best which depicts this problem.

However;

Let use X to represent the time required for the delivery.

Then X~N(3.8 ,0.8)

i.e

E(x) = 3.8

s.d(x) = 0.8

NOW; P(x>4) = P(X-3.8/0.8 > 4-3.8/0.8)

= P(Z > 0.25)

= 1-P(Z < 0.25)

=1 - Φ (0.25)

= 1 - 0.5987 ( from Normal table Φ (0.25) = 0.5987 )

= 0.4013

Thus; the probability a single delivery would take more than 4 hours is 0.4013

What is the z value corresponding to the interval boundary?

The z value is calculated as:

$z = \dfrac{X- \mu}{\sigma}$

$z = \dfrac{4- 3.8}{0.8}$

z = 0.25

3 0

2 years ago