Answer:
-x +8
Step-by-step explanation:
3x + 6 + -4x + 2
Combine like terms
3x-4x +6+2
-x +8
(x + 11) *squared* +(y-12) *squared* = 49
9, 27, 45, 54, 81,
These are the multiples of 9.
9 *1
9 *3
9 *5
9 *6
9 *9
Basically when the object hits the ground, f(t) is equal zero. So all you need to do is to solve the quadratic equation:
-5t^2 + 20t + 60 = 0
D = b^2 - 4ac = 20^2 - 4 × (-5) × 60 = 400 + 1200 = 1600
t1 = (-b + sqrt(D)) / 2a = (-20 + 40) / (-10) = -2
t2 = (-b - sqrt(D)) / 2a = (-20 - 40) / (-10) = 6
Since time can't be negative, our solution is t2.
So the object will hit the ground in 6 seconds.
If a student runs 4K in 1/2 hours, then he would run 8k In 1 hour, so,
8km/h
