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musickatia [10]
3 years ago
12

△ABC is similar to △LMN. Also, angle B measures 35° and angle C measures 95°. What is the measure of angle L?

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0
Triangles are similar meaning their angles are identical and sides may vary.
180deg in any triangle
180-35-95= L and A
ruslelena [56]3 years ago
6 0

When two triangles are similar, the ratio of the corresponding sides are in proportion.

Also the corresponding angles are congruent.

Here we are given that B= 35° & C = 95°

Now by angle sum property

A + B + C = 180°

A + 35 + 95 = 180

A + 130 = 180

Subtracting 130 from both sides, we get

A = 180 - 130

A = 50°.

Now

ΔABC ~ ΔLMN

So by definition of similarity

A = L

But A = 50°.

Hence L = 50°

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What is 1/10 of 0.2 equal
Svetllana [295]
1/10(0.2)

=(1/10)(0.2/1)

=(1)(36028) / (10)(18014)

=0.02


3 0
3 years ago
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Can someone please explain how the answer is D
Kitty [74]

Step-by-step explanation:

Because the length of ST is calculated using pythagorean theorem:

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Where the square of the hypotenuse is equal to the sum of squares of the other two sides of a right triangle. In this case, the hypotenuse is ST and the other two sides are distances between S and T over the X and Y axis. Those are easily calculated:

x =  |sx - tx|  \\ y =  |sy - ty|

Where x is the distance between S and T over X axis and Y distance over Y axis, sx and tx are X coordinates of S and T, sy and ty are Y coordinates of S and T.

Using that formula, you get that y = 17 and x = 8.

Back to the pythagorean theorem, if we put those number in the formula of the pythagorean theorem, we get something like this:

{c}^{2}  =  {x}^{2}  +  {y}^{2} \\  {c}^{2}  =  {8}^{2}  +  {17}^{2} = 64 + 289  \\  {c}^{2}  = 353 \\ c =  \sqrt{353}

And finally, the correct answer is in fact 353.

3 0
2 years ago
Pls help me on this one :((
Nana76 [90]

Answer:

The answer is B) b

Step-by-step explanation:

According to the Trapezoid area formula, the area of the trapezoid is [(2d+a+b) × c] ÷ 2, however the area also equals (d+b) × c.

So d+(a+b)/2=d+b

(a+b)/2=b

a+b=2b

a=b

hope this helps <3

4 0
1 year ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
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babunello [35]

Answer:

1) I believe 6 (im wrong I know it)

Step-by-step explanation:

you do whatever like 13902-1 , im so smart

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