Perimeter of the ΔJKL is 48 cm
Solution:
Given 
.
RS = 8 cm and JK = 12 cm
Perimeter of 
= 32 cm
Let us find the perimeter of 
.
<u>Property of similarity triangles:</u>
If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.
Do cross multiplication.
Divide both sides of the equation by 8.
Hence perimeter of the ΔJKL is 48 cm.
LCM of 5(y - 4)(y + 4) and (y + 4) is 5(y - 4)(y + 4)
-----------------------------------------------------------------------
Answer: 5(y - 4)(y + 4) (Answer D)-----------------------------------------------------------------------
Hey!
----------------------------------------------
Solution:
Remember to follow PEMDAS!
= 3 + 2 ⋅ [(2 + 1) ⋅ 5 + 8]
= 3 + 2 ⋅ [(3) ⋅ 5 + 8]
= 3 + 2 ⋅ [(15) + 8]
= 3 + 2 ⋅ [23]
= 3 + 46
= 49
----------------------------------------------
Answer:
49
----------------------------------------------
Hope This Helped! Good Luck!
Answer:
16.9177% or .169177
Step-by-step explanation:
Binomial i think
10C4*.54⁴*(1-.54)⁶= 16.9177%
Answer:
8900 meters
Step-by-step explanation:
Cuz u move the decimal place back by 3
