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2 years ago

6

Find the measure of angle T to the nearest degree.

1 answer:

irina1246 [14]2 years ago

3 0

Answer:

The answer is option 2.

Step-by-step explanation:

You have to use Cosine Rule, cosθ = adjacent/hypotenuse. Substitute the following value into the formula :

$\cos(θ) = \frac{adj.}{hypo.}$

Let θ = T,

Let adj = 7.5,

Let hypo = 19.5,

$\cos(T) = \frac{7.5}{19.5}$

$T = { \cos( \frac{7.5}{19.5} ) }^{ - 1}$

$T = 67° \: \: (near. \: degree)$

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Nancy also has a mirror that measures 20.32 centimeters long. What is the length of Nancy’s mirror in inches?

tino4ka555 [31]

Answer:

C: 8.00

Step-by-step explanation:

1 in = 2.54 cm

l = 20.32 × 1/2.54

l = 8.00 in

The length of Nancy’s mirror is 8.00 in.

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2 years ago

Pamela is 8 years older that Jiri. The sum of their age is 102. What is Jiri's age?

tresset_1 [31]

Answer:

Step-by-step explanation:

102-8= 94

94/2= 47

Jiri is 47 years old.

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2 years ago

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

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2 years ago

Which of the following is a like radical to 3 sqrt 7x?

san4es73 [151]

Answer:

Options A and B

i.e., A. 4(3 $\sqrt{7x}$ ) and B. $\sqrt{7x}$

Step-by-step explanation:

Like radicals are similar to like terms.

For example,

x, 2x, -10x, $\frac{1}{2} x$ , 7.3x are like terms.

$xy^{2} , -9xy^{2} , 13y^{2} x$ are some more examples of like terms.

Similarly, like radicals are:

$\sqrt{2} , -5\sqrt{2} , 1.1\sqrt{2}$ etc.

Hence, from the given options, like radicals to $3\sqrt{7x}$ are:

A. $4(3\sqrt{7x} )$ and B. $\sqrt{7x}$

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3 years ago

Read 2 more answers

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bixtya [17]

The correct answer is 13.78. You get this by doing 11/cos37.

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2 years ago