The points (2, 5) and (6,-3) fall on a particular line. What is its equation in slope-intercept form?
1 answer:
Answer:
y = -2x + 9
Step-by-step explanation:
slope intercept form : y = mx + b
where m = slope and b = y intercept
first let's find the slope
slope formula :
where the x and y values are derived from the given points
here we are given (2,5) and (6,-3)
(x1,y1) = (2,5) so x1 = 2 and y1 = 5
(x2,y2) = (6,-3) so x2 = 6 and y2 = -3
we now plug these values into the formula
recall formula
plug in x1 = 2, y1 = 5, x2 = 6 and y2 = -3
m = (-3 - 5) / ( 6 - 2 )
m = (-8)/(4)
m = -2
the slope is -2
now to find the y intercept we plug in the slope and the x and y value of a given point into slope intercept form and solve for b
y = mx + b
given point : (2,5) x = 2 , y = 5, m = -2
5 = -2(2) + b
5 = -4 + b
9 = b
so the equation would be y = -2x + 9
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Answer:
If the weight is higher than 5.8886 gr would be considered significantly high
If the weight is lower than 5.6121 gr would be considered significantly low
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
And the best way to solve this problem is using the normal standard distribution and the z score given by:
For the case when z =-2 we can do this:
And if we solve for X we got:
And for the other case when Z=2 we have:
And if we solve for X we got:
If the weight is higher than 5.8886 gr would be considered significantly high
If the weight is lower than 5.6121 gr would be considered significantly low