1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Step-by-step explanation:
<u>1. 5 in and 1/3 in</u>
Here,

<u>2. 5 in and 4/3 in</u>
Here,

<u>3. 5/2 in and 4/3 in</u>

<u>4. 7/6 in and 6/7 in</u>
<u>Let</u>

<u>Hence,</u>
1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Keywords: Rectangle, Area
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a 10-by-10 grid means there are 100 squares and percent is out of 100 so if you have 42% then you just need to fill in 42 squares
Answer:
6 square units
Step-by-step explanation:
Given shape is of a trapezoid:

Area of shape = area of square + area of triangle

Answer:
Step-by-step explanation:
<u>Given recursive formula</u>
- a₁ = 0
- aₙ = 2(aₙ₋₁)² - 1, for n>1
<u>The first 5 terms are:</u>
- a₁ = 0
- a₂ = 2(0)² - 1 = 0 - 1 = -1
- a₃ = 2(-1)² - 1 = 2 - 1 = 1
- a₄ = 2(1)² - 1 = 2 - 1 = 1
- a₅ = 2(1)² - 1 = 2 - 1 = 1
You can use at most 24 beads that are 10 inches long to decorate the rope.
Step-by-step explanation:
Given,
Length of rope = 120 feet
1 foot = 12 inches
20 foot = 20*12 = 240 inches
Length of bead = 10 inches
Let,
x represents the number of beads used on rope.
As the rope is 240 inches long, therefore, the total length of beads cannot exceed 240 inches.
Length of each bead*Number of beads ≤ length of rope

Dividing both sides by 10

You can use at most 24 beads that are 10 inches long to decorate the rope.
Keywords: inequality, division
Learn more about inequalities at:
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