Answer:
one solution with a y value of 5
Step-by-step explanation:
/| x+y-4 = 0| x-y-6 = 0
We try to solve the equation: x+y-4 = 0
x+y-4 = 0 // - x-4
y = -(x-4)
y = 4-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| x+x-6-4 = 0| y = 4-x
2*x-10 = 0 // + 10
2*x = 10 // : 2
x = 10/2
x = 5
We insert the solution into one of the initial equations of our system of equations
For y = 4-x:
y = 4-5
y = -1
We get a system of equations:
/| y = -1| x = 5
I believe the answer is the first one because it’s congruent
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Simplify brackets
(7w - 2 - w = 2(3w - 1)
simplify 7w - 2 - w to 6w - 2
(6w - 2 = 2(3w - 1)
Expand
(6w - 2 = 6w - 2)
Since both sides are equal, there are infinitely many solutions
Answer: C) INFINITELY MANY
Answer:
2y - 15
Step-by-step explanation:
well 15 LESS than TWICE a number. okay so let’s start off by making a variable for the unknown number.... y. the variable is y. so now we have to think, TWICE that number, but we don’t know the number.
Now that we have the variable and we know it has to be doubled, let’s start off making the first half... we can out that into 2y. which is 2 multiplied by the unknown number.
now that we have the first half done, we have to take the 15 less. Less can mean or subtract in this kind of situation. but for this certain scenario, it will be subtraction. so the equation would be 2y - 15.