Question

Cos(2α)*sin(α-β)-cos(β-α)*sin(2α)

Answer 1

Answer:

Step-by-step explanation:

cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)

[cos (-x)=cos x]

sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)

=sin {-(α+β)}

=-sin (α+β)