2 years ago

Cos(2α)sin(α-β)-cos(β-α)sin(2α)

Mathematics

1 answer:

Hunter-Best [27]2 years ago

6 0

Answer:

Step-by-step explanation:

cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)

[cos (-x)=cos x]

sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)

=sin {-(α+β)}

=-sin (α+β)

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Cos(2α)*sin(α-β)-cos(β-α)*sin(2α)

Cos(2α)sin(α-β)-cos(β-α)sin(2α)