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2 years ago

Cos(2α)sin(α-β)-cos(β-α)sin(2α)

Mathematics

1 answer:

Hunter-Best [27]2 years ago

6 0

Answer:

Step-by-step explanation:

cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)

[cos (-x)=cos x]

sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)

=sin {-(α+β)}

=-sin (α+β)

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Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

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Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

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Finding y-intercept

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Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

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Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

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2 years ago

Cos(2α)*sin(α-β)-cos(β-α)*sin(2α)

Cos(2α)sin(α-β)-cos(β-α)sin(2α)