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3 years ago

Cos(2α)sin(α-β)-cos(β-α)sin(2α)

Mathematics

1 answer:

Hunter-Best [27]3 years ago

6 0

Answer:

Step-by-step explanation:

cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)

[cos (-x)=cos x]

sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)

=sin {-(α+β)}

=-sin (α+β)

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1: x=23.313708 2: B x = -13.2 3: x = 152

All the problems examples at the bottom

Step-by-step explanation:

1: 12x=−3(4−x)

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Step 1: Divide both sides by 12.

12x12=3x−1212

x=14x−1

Step 2: Solve Square Root.

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x=−b±b2−4ac2a(Use quadratic formula with a=-0.0625, b=1.5, c=-1)

x=−(1.5)±(1.5)2−4(−0.0625)(−1)2(−0.0625)

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2: 3+2.7x=9.6+3.2x

Step 1: Simplify both sides of the equation.

2.7x+3=3.2x+9.6

Step 2: Subtract 3.2x from both sides.

2.7x+3−3.2x=3.2x+9.6−3.2x

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Step 3: Subtract 3 from both sides.

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Step 4: Divide both sides by -0.5.

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Step 1: Simplify both sides of the equation.

9+34x=78x−10

9+34x=78x+−10

34x+9=78x−10

Step 2: Subtract 7/8x from both sides.

34x+9−78x=78x−10−78x

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Step 3: Subtract 9 from both sides.

−18x+9−9=−10−9

−18x=−19

Step 4: Multiply both sides by 8/(-1).

(8−1)*(−18x)=(8−1)*(−19)

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I really hope this helped you

4 0

3 years ago

Cos(2α)*sin(α-β)-cos(β-α)*sin(2α)

Cos(2α)sin(α-β)-cos(β-α)sin(2α)