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Nadya [2.5K]
3 years ago
6

A minor league baseball team plays 122 games in a season. If the team won 14 more than three times as many games as they​ lost,

how many wins and losses did the team​ have?
Mathematics
1 answer:
Leviafan [203]3 years ago
8 0
W + L = 122
W = 3L + 14

3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games

W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games
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HELP!!!!
Nonamiya [84]
Your answer is E. $25.

First let under 12 = u, over 12 = o, and adults = a.
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2u + 3a + 3o = 174
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Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
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Now that we know what u equals, we can substitute it in to the second equation to get:
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2a = 50
a = $25

I hope this helps! Let me know if you have any questions :)
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