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Crazy boy [7]
3 years ago
13

Prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?

Mathematics
1 answer:
aivan3 [116]3 years ago
5 0
The solution to the problem is as follows:

<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
 
and
 
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA

Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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