3 years ago

Prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?

1 answer:

5 0

The solution to the problem is as follows:

<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA

and

sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA

Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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Answer:

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Step-by-step explanation:

As given

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