3 years ago

Please look at the photo

1 answer:

Anni [7]3 years ago

3 0

We want a 30-60-90 triangle with a perimeter of $8 + 4\sqrt2$ . If the shorter leg has length $x$ , we must have

$x + x\sqrt3 + 2x = 8 + 4\sqrt2\\3x + x\sqrt3 = 8 + 4\sqrt2\\x(3 + \sqrt3) = 8 + 4\sqrt2\\x = \boxed{\frac{8 + 4\sqrt2}{3 + \sqrt3}}$

What a mess.

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dem82 [27]

Answer:

Step-by-step explanation:

In the given triangle

With reference angle A

perpendicular (P) = 3

hypotenuse (h) = 5

So sin A = p/h = 3/5

and

With reference angle C

perpendicular (p)= 4

hypotenuse (h) = 5

Sin C = p/h = 4/5

hope it helps :)

3 0

3 years ago

Goryan [66]

$\frac{4}{5} \ of \ 45= \frac{4}{5} \times 45=4 \times \frac{45}{5}=4 \times 9=36$

4/5 of 45 equals 36.

5 0

4 years ago

nalin [4]

0.06 or 6/100

six hundredths

5 0

4 years ago

Citrus2011 [14]

2 is not a composite number

7 0

4 years ago

ANTONII [103]

$\frac{1}{ {(3k)}^{ \frac{5}{2} } } = {(3k)}^{ - \frac{5}{2} } \\ = \frac{1}{( { \sqrt{3k}) }^{5} } = ({ \sqrt{3k} })^{ - 5}$

5 0

3 years ago