Answer:
-3y/5
Step-by-step explanation:
3/5y+(-6/5y)=
Since the denominator is the same, we can add the numerators
3y - 6y
----------------
5
-3y/5
Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
Answer:
17.7
Step-by-step explanation:
This figure is a pentagon - a shape with 5 sides. In a pentagon, the figure's angles add to 540.
100 + 7x-4 + 3x + 23 + 9x - 6 + 90 = 540
190 +19x + 13 = 540
203 + 19x = 540
19x = 337
x = 17.7
Answer:
12m/s
Step-by-step explanation:
96/8 = 12
Answer:
In every 42 days, Sherman and Brad will go golfing on the same day.
Step-by-step explanation:
Given:
Sherman goes golfing every 6th day.
Brad goes golfing every 7th day.
If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.
Solution:
In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.
To find least common multiple of 6 and 7, we will list out their multiples.
We find out that the least common multiple of 6 and 7 =42.
Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..
