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dimaraw [331]
2 years ago
9

One toothpick is 0.13 inch long, another is 0.33 inch. Which length is greater?

Mathematics
2 answers:
strojnjashka [21]2 years ago
7 0
Well, 0.33 > 0.13.
So, 0.33 inches is greater than 0.13 inches.
anygoal [31]2 years ago
4 0
0.33 is longer than 0.13
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Consider the function f(x)=4x-5. what is the domain value that corresponds to an output of f(x)=11?
erastovalidia [21]
F = 4

if f(x)=11, you must always try and get x alone, so f = (11+5)/4, and this simplifies to 4.
8 0
2 years ago
BRAINLYEST ANSWER
andrew-mc [135]

Answer:

B

Step-by-step explanation:

Multiply 13 into (10-6)= 13*4=52. Now find the number sentence that gives 52. This is B because 13*10 - 13*6 = 13*4 the original problem

3 0
3 years ago
On the average, a certain light bulb is supposed to last 450 hours. If it
Dafna1 [17]

Answer:

72 novels

Step-by-step explanation:

A number of assumptions are involved regarding operating environment, utilization fraction, and probability of failure as a function of time. The precise meanings of the words "average", "supposed to last", "maximum", and "expect" are involved. The details are too arcane to go into here.

 (450 hours)/(6 1/4 hours/novel)

 = (450/(25/4)) novels

 = (450*4/25) novels

 = 72 novels

6 0
3 years ago
Question1) Describe three scenarios that involve a real-world linear or exponential function. At least one must be exponential.
elixir [45]

Answer:

1) Let's suppose that you go in a straight line, in a car that moves at a constant speed of 80km/h.

Then the distance from your house (assuming that you start the drive in your house) can be modeled with a linear equation:

D(t) = 80km/h*t

where t is time in hours.

This will be a linear function.

2) Suppose that you have a population of some animal, that grows by 2% each month, and initially, there are 100 individuals of that animal.

Then the first month, the population is 100.

The second month the population increased by a 2%, then it will be:

100 + 100*0.02 = 100*(1.02)

The third month, the population will be 100*(1.02) + 0.2*100*(1.02) = 100*(1.02)^2.

and so on, this is an exponential relation, where the population as a function of the number of months, can be written as:

P(m) = 100*(1.02)^(m - 1)

3) Suppose that you have $100 saved, and each month you can save another $80, let's find a function that says the amount of money that you have saved as a function of the number of months. S(m)

The month number zero (before you started saving) you had $100 saved.

S(0) = $100.

One month after, you have saved $80 more, then you have:

S(1) = $100 + $80

Another month after, you have:

S(2) = $100 + $80 + $80 = $100 + 2*$80

And so on, you already can see the pattern, after m months, you will have:

S(m) = $100 + m*$80 saved.

5 0
2 years ago
David has been driving for 4 hours at 62.8 km/hr. How many kilometers did he travel in that time?
Murrr4er [49]
I would say 234.221 hshevvwosfueoe
7 0
3 years ago
Read 2 more answers
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