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Usimov [2.4K]
2 years ago
7

According to the College Board, SAT mathematics scores from the 2014 school year for high school students in the United States w

ere normally distributed with a mean of 513 and a standard deviation of 120. Use a standard normal table such as this one to determine the probability that a randomly chosen high school student who took the SAT in 2014 will have a mathematics SAT score between 400 and 750 points.
SAT
1 answer:
Lena [83]2 years ago
7 0

Answer:

80.25%

Explanation:

Data provided in the question

X \sim N (513,120)

Mean = 513

Standard deviation = 120

Now

P(400 < x < 750) = P (\frac{400 - 513}{120}

After solving this

= P (-0.9417 < Z < 1.975)

= P (-0.9417 < Z < 0) + P (0 < Z < 1.975)

= 0.3264 + 0.4761

or by apply the Z table or excel command

Like this

NORMSDIST(1.98) - NORMSDIST(-0.94)

= 0.9761 - 0.1736

= 80.25%

Hence the probability is 80.25%

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The approximations T8 and M8 for the given integral are:

  • T8 = 33.386321; and
  • M8 = 33.50794

<h3>What is an integral?</h3>

An Integral is a variable of which a given function is the derivative, i.e. it gives that function when differentiated and may express the area under the curve of the function's graph.

<h3>What is the explanation to above answer?</h3>

Given:

F(x) = 37 cox (x²)

Internal = [0,1] n = 8 in Δ x = 1/8

The sub intervals are:

[0, 1/8], [1/8, 2/8], [2/8, 3/8], [ 3/8, 4/8], [ 4/8, 5/8], [ 5/8, 6/8], [6/8, 7/8], [ 7/8, 1]

The mid points are given as:

1/16, 3/16, 5/16, 7/16, 9/16, 11/16, 13/16, 15/16

and X₀ = 0, X₁ = 1/8, X₂ = 2/8

Using the Trapezium Rule which states that:

\int\limits^1_0 cos(x)^{2} } \, dx = Δx/2 [f(xo) + 2f(x1) 2f(x2) + ....+ 2f(x7) + f(x8)]

= 1/1Q[f(0) + 2f (1/8) + 2f(2/8) + ....+ 2f(7/8) + f(1)]

= 0.902333

Now

T8 = \int\limits^1_0 {37Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {(0.902333)} } \, dx

= 37 (0.902333)

T8 = 33.386321

It is to be noted that the midpoints rule is given as;

\int\limits^1_0 {Cos(x)^{2} } \, dx  = Δx [f(1/16) + (3/16) + .... + f(15/16)]

= 1/8[f(1/16) + f (3/16) + f(5/16) + f(7/16) + f(9/16) + f(11/16) + f(13/16) + f(15/16)]

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From the above,

M8 = \int\limits^1_0 {37 Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {Cos(x)^{2} } \, dx

= 37 (0.905620)

M8 = 33.50794

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