Answer:
The second choice
Step-by-step explanation:
###### ### ### ##### #### ###### #### #### :)
<em>NOT VALID</em>
Answer:
x=2, y=1
Step-by-step explanation:
2x + y = 5
5x − 2y = 8.
Multiply the first equation by 2
2( 2x + y) = 5*2
4x +2y = 10
Add this to the 2nd equation to eliminate y
4x+2y = 10
5x -2y = 8
--------------------
9x = 18
Divide by 9
9x/9 = 18/9
x = 2
Now find y
2x+y = 5
2(2)+y = 5
4+y = 5
Subtract 4 from each side
y = 5-4
y =1
If α and β are the Roots of a Quadratic Equation ax² + bx + c then :
✿ Sum of the Roots : α + β 
✿ Product of the Roots : αβ 
Let the Quadratic Equation we need to find be : ax² + bx + c = 0
Given : The Roots of a Quadratic Equation are 6 and 3
⇒ α = 6 and β = 3
Given : The Leading Coefficient of the Quadratic Equation is 4
Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2
Leading Coefficient of our Quadratic Equation is (a)
⇒ a = 4
⇒ Sum of the Roots 
⇒ -b = 9(4)
⇒ b = -36
⇒ Product of the Roots 
⇒ c = 18 × 4
⇒ c = 72
⇒ The Quadratic Equation is 4x² - 36x + 72 = 0
Answer:
y = 4/3x - 10.
Step-by-step explanation:
3x + 4y = 12
4y = -3x + 12
y = -3/4x + 3
If a line is perpendicular to another, the line has a slope that is the negative reciprocal of the other line. Since the given line has a slope of -3/4, the line perpendicular to that line will have a slope of 4/3.
So far, for the equation of the line, we have an equation of y = 4/3x + b.
To find b, simply substitute the coordinates (6, -2) for x and y.
-2 = 4/3(6) + b
b + 4/3(6) = -2
b + 8 = -2
b = -10
So, the equation of the line will be y = 4/3x - 10.
Check your work...
-2 = (4/3)(6) - 10
-2 = 8 - 10
-2 = -2
Hope this helps!