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Marysya12 [62]
2 years ago
6

Shera is building a cabinet. She is making wooden braces for the corners of the cabinet. Find the surface area of each brace. 1

by 3, 1 by 3, 3 by 3, 1 by 1
Mathematics
1 answer:
ahrayia [7]2 years ago
7 0
The answer is 16 hope  it helps
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What is <br> 6 3/5<br><br> Write your answer as a mixed number.
galina1969 [7]

Answer:

33/5

Step-by-step explanation:

6 3/5 = 33/5

6 x 5 = 30

30 + 3 = 33

33/5.

4 0
2 years ago
Read 2 more answers
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Mary had a back surgery and was given a prescription with instructions to take 4 tablets twice a day for pain. How many tablets
astraxan [27]

Answer:

14 tablets

Step-by-step explanation:

In one day 2 tablets and in 7 day

7×2=14 tablets

4 0
3 years ago
PLEASE HELP ME IF YOU CAN! please tell me how you got the answer thank you!
Temka [501]
3sqrt(2)

You can either use Pythagorean theorem or special triangle proportions to find the side that is parallel to z. Since in a 45-45-90 degree triangle, the hypotenuse is the leg times the square root of 2, and the hypotenuse is 3, we know that the leg is 3/sqrt(2) which is equal to 3 sqrt(2) / 2. Since z is twice this length, we know that z is equal to 2 x 3sqrt(2)/2 = 3sqrt(2)
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2 years ago
If it is warm outside, then I will not wear my jacket.
9966 [12]

If it's cold outside, then then I will wear my jacket.

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