group the 1st 2 terms and last 2 terms:
(Z63 -2z^2) + (9z-18)
factor out GCF:
z^2(z-2) + 9(z-2)
now factor the polynomial:
(z-2) (z^2+9)
Answer:
The answer is 31 pennies
Step-by-step explanation:
we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.
The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:
1) factor: 5 (+1) = 6
6 ÷ 2 = 3 remainder 0
6 ÷ 3 = 2 remainder 0
since there is a remainder of 0, when divided by 3, 6 is wrong
2) factor; 10 (+1) = 11
11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer
3) factor : 15 (+1) = 16
16 ÷ 2 = 8 remainder 0 ( 16 is not the correct answer
4) factor : 20(+1) = 21
21 ÷ 3 = 7 remainder 0 ( 21 is wrong)
5) factor : 25(+1) = 26
26 ÷ 2 = 13 remainder 0 ( 26 is wrong)
6) factor : 30(+1) = 31
31 ÷ 2 = 15 Remainder 1
31 ÷ 3 = 10 Remainder 1
31 ÷ 5 = 6 Remainder 1
since all three divisors give a remainder of 1, the correct answer is 31
Therefore you have 31 pwnnies
Answer:
its the one with 2000$ in it
Step-by-step explanation:
Answer:
9400
Step-by-step explanation:
I'm not really sure if this is right but I changed 0.2% to 1/5 and 1/5 is 9400. Hope this is right!
volume = 4/3 x PI x r^3
r = 10/2 =5
V = 4/3 x 3.14 x 5^3 = 523.333
523.3 cubic inches
