Answer:
B. I and III
Step-by-step explanation:
I and III both have the same data:
March, 73
April 74
May 78
June 84
July 75
II has different data
March 71
April 72
May 85
June 90
July 60
Since I and III have the exact same data, choice B is the best answer
Hope this helps! :)
For the first part:
if w is width and length is 2 times that, what would the length be?
For the second part:
we know that the perimeter is less-than 48in, so we can start by saying
something<48
next you have to determine what that something is: the perimeter.
To find perimeter, you add the length of the sides. We already know that there are two sides which measure 'w' units, and two sides which measures are the expression you're finding in the first part. So, you simply need to add these together!
width + width + length + length<48.
(Note: you'll obviously want to replace the words width and length with the values for the width and length; in the case of width, the value is given in the problem in the form of a variable, and the length is the expression you solve for in the first part.
You should be able to solve to find the expression from the first part on your own, and once you have those, simply plug the value of the width and the length into the expression. Rather than just giving you the answer, this allows you to still work it out on your own to a certain extent.
Make sense? (:
Answer:
If the outlier is included in the data, the mean would not change.
Step-by-step explanation:
Answer:
#1
<u>Correct choice is </u>
#2
<u>Correct choice is</u>
#3
<u>Correct choice is</u>
#4
<u>Correct choice is</u>
- B. ∠WYX and ∠WYZ are linear pairs
#5
<u>Correct choice is</u>
Answer : The Susana swam the fastest.
Step-by-step explanation :
Speed : It is defined as the distance traveled per unit time.
Formula used :
First we have to determine speed of the following persons.
<u>For Tawni :</u>
Distance = 50 m
Time = 40.8 s
The speed of Tawni is, 1.225 m/s
<u>For Pepita :</u>
Distance = 100 m
Time = 60.2 s
The speed of Pepita is, 1.661 m/s
<u>For Susana :</u>
Distance = 200 m
Time = 112.4 s
The speed of Susana is, 1.779 m/s
From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.
Thus, Susana swam the fastest.
