Answer:
(2f-17h)/24k
Step-by-step explanation:
We can make the common denominator for 3k and 8k in the form of 24k, so we get (multiply the first fraction by 8 and the second one by 3 to get 24k on each denominator) (8f-32h)/3k-(6f-15h)/24k. Now we can just subtract the numerators :
8f-32h-6f+15h (sign gets flipped on 6f and 15h), so we get
(2f-17h)/24k
Answer:
Step-by-step explanation:
(8x²-18x+10)/(x²+5)(x-3)
express the expression as a partial fraction:
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5
both denominator are equal , so require only work with the nominator
(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)
8x²-18x+10= x²A+5A+bx²+cx-3bx-3c
combine like terms:
x²(A+b)+x(-3b+c)+5A-3c
(8x²-18x+10)
looking at the equation
A+b=8
-3b+c=-18
5A-3c=10
solve for A,b and c (system of equation)
A=2 , B=6, and C=0
substitute in the value of A, b and c
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5
(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)
(8x²-18x+10)/[(x^2+5)(x-3)] =
<h2>2/(x-3)+6x/x²+5</h2>
(4x+2)/[(x²+4)(x-2)]
(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)
(4x+2)=a(x²-2)+(bx+c)(x-2)
follow the same step in the previous answer:
the answer is :
<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>
The answer will be letter C
Answer:
D
Step-by-step explanation:
An angle of depression is measured from the horizontal downwards.
this is angle D in the diagram
End behavior always involves x approaching positive and negative infinity. So we'll cross off the choice that says "x approaches 1".
The graphs shows both endpoints going down forever. So both endpoints are going to negative infinity regardless if x goes to either infinity.
<h3>Answer: Choice B</h3><h3>As x approaches −∞, f(x) approaches −∞, and as x approaches ∞, f(x) approaches −∞.</h3>
Another way to phrase this would be to say "f(x) approaches negative infinity when x goes to either positive or negative infinity"
