Solve for t in terms of q, r, and s. S = rqt T=

A rectangular stained glass window is made up of identical triangular parts as pictured below.

Pachacha [2.7K]

36/4=9 48/3=16 so 9*16=144/2=72 so it is 72 square inches

3 0

3 years ago

Which steps could be used to solve this story problem? Krissy had 32 bagels. She gave an equal number of bagels to each child. T

Elina [12.6K]

D, because it said that Krissy had equally distributed the bagels to each child, so 32/8=4, and then it asked how many bagels did the girls get all together, so it's 4x3=12

4 0

3 years ago

Read 2 more answers

A chocolate manufacturer sells a 320g ar of chocolate for 50p. The size of the bar is reduced by 20%, and the price to 42p.

Contact [7]

Answer:

less value

Step-by-step explanation:

To deterimine if value was improved or not, we need to compare the price reduction to the size reduction.

__

The reduction in price is ...

((new value)/(old value) -1) × 100%

= (42/50 -1) × 100% = -16%

The size reduction of 20% is more than the price reduction of 16%, so the chocolate bar is less value.

_____

Additional comment

Compared to the original value, the new price to chocolate ratio is ...

0.84/0.80 = 1.05

Effectively, the price was raised by 5%.

6 0

2 years ago

(Problem of the Week)

ira [324]

Answer:

He won 13 times and lost 1 time

Step-by-step explanation:

divide 67 by 5 so 67÷5 you would get 13.4 you take the whole number 13 and multiply it by 5 and that will get you to 65 so then you only have 2 left over and if you lose you get 2 point so therefore you know that he lost only once

(13•5)+2=67

5 0

3 years ago

Jeremy analyses one of his parachute jumps. He draws a graph showing his velocity up to the opening of his parachute. a) Estimat

jeyben [28]

Answer:

Jeremy's acceleration is about $1\,\frac{m}{s^2}$ at t =10 s

His average speed is about 44.5 m/s in this section of his jump approximating with points on the curve (under-estimate)

His average speed is about 46 m/s if using the tangent line (over estimate)

Step-by-step explanation:

Jeremy's acceleration can be estimated by the curve's derivative at that point. That is the slope of the tangent line to the velocity curve at x = 10 sec. Please see attached image where the tangent line is drawn in orange, and the points to use to calculate its slope are drawn in green.

These points are : (6, 42) and (14,50) which using the slope formula give:

$slope=\frac{y_2-y_1}{x_2-x_1}= \frac{50-42}{14-6}=\frac{8}{8} \frac{m}{s^2} = 1\,\frac{m}{s^2}$

So his acceleration at that point is about $1\,\frac{m}{s^2}$

Now, using about the same interval of x-values (from 6 to 14), the corresponding speeds are approximately: 40 (for time 6 seconds) and 49 (for time 14 seconds (look for the red dots on the attached image). Since the average velocity is given by the integral of the function between those points divided by the length of the interval where it is calculated:

$v_{average}=\frac{area}{interval\,\,length}$

and we don't have the actual velocity function to estimate the integral, we can approximate this area by that of a trapezoid that connects the red dots with the bottom of the horizontal axis (see red trapezoid in the image). Clearly from the image, this approximation would give us an under-estimate of the actual average speed.

The area of this trapezoid is: approximately:

$Trapezoid\,\, area=(49+40)\,8/2=356$

Then the average velocity estimated from it is:

$v_{average}=\frac{356}{8} \frac{m}{s} =44.5\,\frac{m}{s}$

If the area is approximated instead with the trapezoid form by the green points we used to calculate the acceleration (this would give us an over-estimate):

$Trapezoid\,\, area=(50+42)\,8/2=368$

Then the average velocity estimated from it is:

$v_{average}=\frac{368}{8} \frac{m}{s} =46\,\frac{m}{s}$

while his actual instantaneous velocity seems to be about 46 m/s from the graph

4 0

3 years ago