All categories

1 year ago

Which systems have infinite solution? check all that apply

Mathematics

2 answers:

Sergeu [11.5K]1 year ago

7 0

Answer:

Step-by-step explanation:

sveta [45]1 year ago

7 0

Answer:

Ok got it

Step-by-step explanation:

the answers are y = 0.5x + 2.75 and y – 0.5x = 2.75

y = 0.5x + 2.75 and y = 0.5(x + 5.5)

y = 0.5x + 2.75 and y = –2(–0.25x )+ 2.75

You might be interested in

Two sides of a rectangle are 4cm in length. The other two sides are 6cm in length. What is the perimeter of the rectangle? Inclu

mr Goodwill [35]

Answer: 200 mm

Step-by-step explanation:

The perimeter of rectangle is given by :-

$P=2(l+w)$ , where l is length and w is width of the rectangle.

Given : Two sides of a rectangle are 4 cm in length. The other two sides are 6 cm in length.

The perimeter of the rectangle will be :_

$P=2(4+6)=2(10)=20\ cm$

We know that 1 cm = 10 mm

Therefore, perimeter of the rectangle = $20\times10=200\ mm$

8 0

3 years ago

Help me pls fast ASAP

lidiya [134]

Um... I beleive its A due to 2x times 3x with an exponet of 2 would make 6x with the exponet of 2 then you would add 5

8 0

3 years ago

Each big square is cut into 3 parts to represent multiplying by one-third. The number of small shaded squares in the circled par

sammy [17]

Answer:the answer is 5/9

Step-by-step explanation:

8 0

3 years ago

If 1,000 gallons of oil cost $4,861, what is the cost of 35 gallons

Paul [167]

Answer:

$170.14

Step-by-step explanation:

4,861 / 1,000 = $4.861 per gallon

35 x $4.681 = $170.135, so you need to round up to the nearest penny

6 0

2 years ago

Read 2 more answers

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

2 years ago