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3 years ago

Expressions equivalent to 3a+9a+7b-bPLS HELP DUE TONIGHT

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

Answer:

12a + 6b

Step-by-step explanation:

Combine like terms

12a+7b-b

Combine like terms

12a+6b

Hence, 12a+6b = 3a+9a+7b-b

[RevyBreeze]

Vlad1618 [11]3 years ago

7 0

ANSWER: ⇒ 12a + 6b

Simplify or expand:

3a + 9a + 7b - b

Reorder and gather like terms:

(3a + 9a) + (7b - b)

Collect coefficients of like terms:

(3 + 9) × a + (7 - 1) × b

Calculate the sum or difference:

12a + (7 - 1) × b

Calculate the sum or difference:

12a + 6b

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Answer:

Case 1:

$AB = 30$

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Case 2:

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Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

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Take square roots of both sides

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$AC^2 = AN^2 + NC^2$

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$1600 = 576 + NC^2$

Collect like terms

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$NC^2 = 1024$

Take square roots

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So:

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Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

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$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

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