Can someone help me with this math homework please!

F(x) = x2 + 4x + 3 symmetry of -2

Brrunno [24]

Answer:

IDK

Step-by-step explanation:

search up yt vid or use https://www.mathpapa.com/algebra-calculator.html

7 0

3 years ago

How do you interpret a decimals meaning as a ratio as a ratio<br> How do you interpret 0.003

agasfer [191]

The 3 is in the one-thousandths place.
You can call this number "zero point zero zero three."
Since the 3 is in the thousandths place, this number can also be called "three thousandths."
Use the name of the number to find the ratio.
"three thousandths" means 3 out of 1000.
The ratio is 3:1000 or 3/1000.

4 0

3 years ago

Caroline’s two managers, Shawna and Morris, are having a meeting to discuss her performance. To prepare, Morris looks at Carolin

PSYCHO15rus [73]

I believe the answeris B

7 0

3 years ago

Read 2 more answers

The angle measure in degrees that corresponds to 7/10ths of a circle is what?

Serggg [28]

7/10 of the degrees of a circle is 252 . I dont know the second part of the question sorry.

8 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

3 years ago