perimeter = 2L + 2W
L=8+w
perimeter = 2(8+w) +2w
80 =16+2w+2w
80 = 16 +4w
64 =4w
w=64/4 = 16
l=16+8 =24
length = 24 feet
width = 16 feet
check 2(24) +2(16) = 48 + 32 = 80
We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
Answer:
last row equals 333
Step-by-step explanation:
The clock showing time 9:00 should be worth 9 points, and the clock showing 3:00 should be worth 3 points, giving for the first row:
9 + 9 + 3 = 21
the three equal calculators showing 1234 are worth 10 points each:
1+2+3+4 = 10
and 10 + 10 + 10 = 30
the light bulbs should be 15 points each then giving 15 + 15 - 15 = 130 - 15 = 15 Notice also that they all have 5 rays of light coming out (so a 3 points per ray)
Now for the bottom line we have:
9 + (1+2+2+4) times 3 * 12 (only four rays on each bulb thus 4 * 3 = 12)
Notice we added the figures that appear in the calculator.
9 + 9 * 36 = 333
Answer:
8x-15y=84
Step-by-step explanation:
Multiply 12 to both sides to get rid of the fractions.
