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2 years ago

Anyone help me please

Mathematics

1 answer:

andrew11 [14]2 years ago

4 0

Solution,

As we have,

⇒2SinACosB=Sin(A+B)+Sin(A-B)

Now,

$2sin7\alpha .cos2\alpha =sin9\alpha +sin5\alpha \\\\LHS=2sin7\alpha .cos2\alpha \\\\LHS=sin(7\alpha +2\alpha )+sin (7\alpha -2\alpha )\\\\LHS=sin9\alpha +sin5\alpha$

Hence, LHS=RHS

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