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1 year ago

To make a bakery's signature chocolate muffins

Mathematics

1 answer:

garri49 [273]1 year ago

7 0

Become a ninja sneak in and steal their recipe and get out and don't get caught. - VEX

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Twenty- four divided by the difference between 1 1/2 and 3/4

NISA [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

7.935 x 10 to negative 5 power

Effectus [21]

Answer:

0.00007935

Step-by-step explanation:

7.935 x 10 to negative 5 power can be written as:

7.935 x 10^(-5)

$7.935*10^{-5}\\\frac{7.935}{10^5}$

A trick to finding 10 to the x power, x is the number of 0's. So 10^5 = 100000

$\frac{7.935}{100000}\\$

When dividing by tens, move the decimal to the left by the amount of 0's

So our answer is 0.00007935

5 0

3 years ago

The number of stamps that kaye and alberto had were in the ratio 5 : 3, respectively. after kaye gave alberto 10 of her stamps,

Gala2k [10]

K:A
5:3 (before)
15:9

since the total number of stamps didn't change, the total ratio should be the same.

7:5(after)
14:10

so this means 1 unit is 10stamps.

14-10=4
4 X 10= 40

Kaye have 40 more stamps than Alberto.

4 0

2 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

7 0

2 years ago

8. Where will the hour hand of a clock stop if it starts:

Virty [35]

Answer:

a. 11

b. 9

Step-by-step explanation:

thats the answer

3 0

2 years ago