The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.
<h3>
Simplification</h3>
Question 1: a³ - 1000b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 1000 is the cube of 10
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(a - 10b) × (a² + 10ab + 100b²)
Question 2: 64a³ - 125b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 64 is the cube of 4
- 125 is the cube of 5
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(4a - 5b) • (16a² + 20ab + 25b²)
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Answer:
32115
Step-by-step explanation:
Step1
Converting 431 to base 10.
4*102=400
3*101=30
1*100=1
Adding all to get Ans=43110
Step2 converting 43110 to 5
The equation calculation formula for 43110 number to 5 is like this below.
5|431
5|86|1
5|17|1
5|3|2
5|3|3
Ans:32115
Because then it would be easier to get an answer for a problem
Numbers are 416, 417 and 418
<u>Step-by-step explanation:</u>
Step 1:
Let the numbers be x, x + 1 and x + 2. Given that their sum is 1251.
⇒ x + x + 1 + x + 2 = 1251
⇒ 3x + 3 = 1251
⇒ 3x = 1248
⇒ x = 416
Step 2:
Find the other numbers.
⇒ x + 1 = 417 and x + 2 = 418
Answer:
3.3h-3.1d-17
Step-by-step explanation:
