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evablogger [386]
4 years ago
9

in how many different ways can t e letters of the word "LEADING" be arranged in such a way that vowels always come together?

Mathematics
2 answers:
Scorpion4ik [409]4 years ago
5 0
The word 'LEADING' has 7 different letters.  When the vowels EAI are always together, they can be supposed to form one letter.  Then, we have to arrange the letters LNDG (EAI).  Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.  The vowels (EAI) can be arranged among themselves in 3! = 6 ways. <span> Required number of ways = (120 x 6) = 720.  The word 'LEADING' can be arranged 720 different ways in such a way that vowels always come together. </span>
soldi70 [24.7K]4 years ago
5 0
We have 3 vowels. The number of ways we can arrange them so they are next to each other is 3!=6. Now we have to find the number of ways we can arrange these 3 vowels with the remaining letters. As the vowels have to come together, we can treat them as one letter. Therefore we have 5 letter altogether. The number of ways we can arrange the vowels with the remaining letters is 5!=120. 

6*120=720

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P(A)* P(B)≠ p(AnB)<br><br> Why does it contain a not equal to sign
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P(A|D) and P(D|A) from the table above are not equal because P(A|D) =  and P(D|A) =

Step-by-step explanation:

Conditional probability is the probability of one event occurring  with some relationship to one or more other events

.

P(A|D) is called the "Conditional Probability" of A given D

P(D|A) is called the "Conditional Probability" of D given A

The formula for conditional probability of P(A|D) = P(D∩A)/P(D)

The formula for conditional probability of P(D|A) = P(A∩D)/P(A)

The table

              ↓         ↓       ↓

           :  C     :   D    : Total

→ A      :  6     :    2    :   8

→ B      :  1      :    8    :   9

→Total :  7     :    10  :  17

∵ P(A|D) = P(D∩A)/P(D)

∵ P(D∩A) = 2 ⇒ the common of D and A

- P(D) means total of column D

∵ P(D) = 10

∴ P(A|D) =

∵ P(D|A) = P(A∩D)/P(A)

∵ P(A∩D) = 2 ⇒ the common of A and D

- P(A) means total of row A

∵ P(A) = 8

∴ P(D|A) =

∵ P(A|D) =

∵ P(D|A) =

∵   ≠  

∴ P(A|D) and P(D|A) from the table above are not equal

Step-by-step explanation:

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