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kozerog [31]
3 years ago
12

I need help ASPA 100 PTS.

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

i can barely see whats on the paper if take a pic of it better then ill help you answer it

Step-by-step explanation:

You might be interested in
1 2/5m - 3/5(2/3m+1)
erastova [34]

Answer:

step by step

STEP

1

:

Equation at the end of step 1

((((3•(m3))+5m2)-5m)+1)

(———————————————————————•m)-1

3

STEP

2

:

Equation at the end of step

2

:

(((3m3+5m2)-5m)+1)

(——————————————————•m)-1

3

STEP

3

:

3m3 + 5m2 - 5m + 1

Simplify ——————————————————

3

Checking for a perfect cube :

3.1 3m3 + 5m2 - 5m + 1 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 3m3 + 5m2 - 5m + 1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -5m + 1

Group 2: 5m2 + 3m3

Pull out from each group separately :

Group 1: (-5m + 1) • (1) = (5m - 1) • (-1)

Group 2: (3m + 5) • (m2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(m) = 3m3 + 5m2 - 5m + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of m for which F(m)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers m which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 3 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1,3

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 8.00

-1 3 -0.33 3.11

1 1 1.00 4.00

1 3 0.33 0.00 3m - 1

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

3m3 + 5m2 - 5m + 1

can be divided with 3m - 1

Polynomial Long Division :

3.4 Polynomial Long Division

Dividing : 3m3 + 5m2 - 5m + 1

("Dividend")

By : 3m - 1 ("Divisor")

dividend 3m3 + 5m2 - 5m + 1

- divisor * m2 3m3 - m2

remainder 6m2 - 5m + 1

- divisor * 2m1 6m2 - 2m

remainder - 3m + 1

- divisor * -m0 - 3m + 1

remainder 0

Quotient : m2+2m-1 Remainder: 0

Trying to factor by splitting the middle term

3.5 Factoring m2+2m-1

The first term is, m2 its coefficient is 1 .

The middle term is, +2m its coefficient is 2 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 1 • -1 = -1

Step-2 : Find two factors of -1 whose sum equals the coefficient of the middle term, which is 2 .

-1 + 1 = 0

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

:

(m2 + 2m - 1) • (3m - 1)

(———————————————————————— • m) - 1

3

STEP

4

:

Equation at the end of step 4

m • (m2 + 2m - 1) • (3m - 1)

———————————————————————————— - 1

3

STEP

5

:

Rewriting the whole as an Equivalent Fraction

5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

1 1 • 3

1 = — = —————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

m • (m2+2m-1) • (3m-1) - (3) 3m4 + 5m3 - 5m2 + m - 3

———————————————————————————— = ———————————————————————

3 3

Polynomial Roots Calculator :

5.3 Find roots (zeroes) of : F(m) = 3m4 + 5m3 - 5m2 + m - 3

See theory in step 3.3

In this case, the Leading Coefficient is 3 and the Trailing Constant is -3.

The factor(s) are:

of the Leading Coefficient : 1,3

of the Trailing Constant : 1 ,3

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -11.00

-1 3 -0.33 -4.04

-3 1 -3.00 57.00

1 1 1.00 1.00

1 3 0.33 -3.00

3 1 3.00 333.00

Polynomial Roots Calculator found no rational roots

Final result :

3m4 + 5m3 - 5m2 + m - 3

———————————————————————

3

Terms and topics

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7 0
3 years ago
The ratio of the heights of two similar cylinders is 1:3. If the volume of the smaller cylinder is 67 cubic cm, find the volume
Andreyy89
The volume is 18.72
8 0
3 years ago
The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit
garik1379 [7]

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.


6 0
3 years ago
A frequency table for the 30 best lifetime baseball batting averages of all time is shown to the right. These data can be graphi
Mashcka [7]

Answer: B

Step-by-step explanation:

Histogram is a statistical graph with the use of bar. The bar are not seperated unlike bar chart.

0.320 to 0.329 and 0.360 to 0.369 are of the same frequency which is equal to one. 0.350 to 0.359 is of frequency 2 a little above frequency 1.

Option B and D are very close to each other in value representation. But the frequency of 0.350 to 0.359 in option D is 3. This renders option D invalid and make option B the correct answer.

5 0
3 years ago
Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution
Iteru [2.4K]

Consider the equation:

\sqrt{x+2}+4 = 8

Subtracting '4' from both the sides of the equation, we get as

\sqrt{x+2}+4-4= 8-4

\sqrt{x+2}= 4

Squaring on both the sides of the equation, we get

(\sqrt{x+2})^2 = (4)^2

x+2 = 16

Subtracting '2' from both the sides of the equation, we get

x+2-2=16-2

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0
3 years ago
Read 2 more answers
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