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Viefleur [7K]
3 years ago
5

Will has 40 state quarters if 3/5 of his quarters are dated 2005 what is the value of the quarters from 2005?

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

5.75

thats just the answer

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martin pidio 1/8 de kg de clavos de 1/2 pulgada si la bascula es digital y pesa en kilogramos ¿cuantos tienes q marcar en este c
love history [14]

Martin will have to mark 0.125 on the

Let the original weight of the scale be 1kg. Hence we can say the original mark for 1kg weight is 1 that is:

1kg = 1 ................ 1

Since we are to calculate where to mark for a 1/8 kg weight, we can write;

1/8 kg = x  ..................2

Divide both expressions

\frac{1}{1/8}= \frac{1}{x}\\\\Cross \ multiply\\8= \frac{1}{x} \\x =  \frac{1}{8}

This means Martin will have to mark 0.125 on the scale.

Learn more here: https://brainly.lat/tarea/13002863

3 0
2 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
\log_{4} x + \log_{4} (x+5) = 6
irina1246 [14]
       log(4)x + log(4)(x + 5) = 6
log(4)x + log(4)x + log(20) = 6
               log(8)x + log(20) = 6
               <u>            - log(20)  - log(20)</u>
                              <u>log(8)x</u> = <u>6 - log(20)</u>
                               log(8)         log(8)
                                       x ≈ 0.999
8 0
3 years ago
What is the area of the polygon below?
Julli [10]

Answer:

A. 147

Step-by-step explanation:

Divide the polygon into rectangles.

You will have 2 rectangles:

1) 3 x 10

2) 9 x 13

Now you just need to find the area of this 2 rectangles and add them up.

6 0
1 year ago
What is the area of this
frosja888 [35]

Answer:

615... just add them all and add 20.

8 0
2 years ago
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