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2 years ago

10

A golf ball weighs about 45.9 grams. About how many ounces would a dozen golf balls weigh?

1 answer:

laila [671]2 years ago

3 0

Answer:

about 55 grams.

Step-by-step explanation:

you do 45.9 times 12 because a dozen is twelve

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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

3 years ago

The volume of a cone, V , varies jointly with its height, h , and the square of its

Paha777 [63]

Answer: v = k•r^2•h

Step-by-step explanation:

8 0

3 years ago

A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp

Volgvan

Answer: $1+10(1-\cos (\frac{\pi t}{9}))$

Step-by-step explanation:

Given

radius of wheel $r=10 m$

Time period of Wheel $T=18 s$

and $T\cdot \omega =2\pi$ , where $\omega =angular velocity of wheel$

$\omega =\frac{2\pi }{18}$

Let at any angle $\theta$ with vertical position of a point is given by

$x=r\sin \theta$

$y=y_0+r(1-\cos \theta )$

and $\theta =\omega \times t$

for velocity differentiate x and y to get

$v_x=r\cos \theta =r\cos (\omega t)$

$v_y=0+r(\sin \theta )=r\sin (\omeag t)$

Height at any time t is given by

$h=1+10(1-\cos \theta )=1+10(1-\cos (\frac{\pi t}{9}))$

7 0

3 years ago

What is the measure of ∠R ?

GarryVolchara [31]

You want to find R. From angle R, you know the side lengths for opposite and hypotenuse. According to SohCahToa, that is sine. Sin (x) = Opposite / Hypotenuse = 2.5 / 5 = 0.5
Sine(x)=.5. To get x by itself divide both by the inverse of sine.

3 0

3 years ago

Read 2 more answers

Suppose you need to minimize the cost of fencing in a rectangular region with a total area of 450 square feet. The material that

natta225 [31]

Answer:

The problem is stated as:

Min C = 15*(2*x +y) + 21*y

subject to x*y = 450

Step-by-step explanation:

Given that the region is rectangular, it has two opposite sides called x and two other opposite sides called y (both measured in feet). Then, the area (in square feet) is:

A = x*y = 450

One of the sides called y costs $21 per linear foot. The other 3 sides (two x and one y) costs $15 per linear foot. Then, the cost function is:

C = 15*(2*x +y) + 21*y

5 0

3 years ago