Plz help quickly no time only I need the answer

yaroslaw [1]

Answer:

$b = \dfrac{a - 10c}{10}$

Step-by-step explanation:

$\begin{array}{rcl}5 & = & \dfrac{a}{2(b + c)}\\\\5& = & \dfrac{a}{2b + 2c}\\\\10b + 10c & = & a\\10b & = & a - 10 c\\b & = & \mathbf{\dfrac{a - 10c}{10}}\\\end{array}$

8 0

3 years ago

Use the graph representing bacteria decay to estimate the domain of the function and solve for the average rate of change across

kykrilka [37]

0 < x < 18 , - 3 . 33

3 0

3 years ago

Read 2 more answers

( -20 , 14 ) and ( 30, 18) Slope, Explanation needed please HELPPPPPP

Morgarella [4.7K]

Answer: 2/25

Step-by-step explanation:

The formula to find the slope is (y2-y1)/(x2-x1)

If you plug in the numbers, you get (18-14)/(30-(-20))

Solve the expression and you get 4/50 = 2/25

So your answer is 2/25

6 0

3 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago

Round the answer to the nearest

kykrilka [37]

By knowing the blood pressure and applying the quadratic formula, the age of a man whose normal blood pressure is 129 mm Hg is 40 years old.

<h3>How to use quadratic equations to determine the age of a man in terms of blood pressure</h3>

In this problem we have a quadratic function that models the blood pressure as a function of age. As the latter is known, we must use the quadratic formula to determine the former:

129 = 0.006 · A² - 0.02 ·A + 120

0.006 · A² - 0.02 · A - 9 = 0

$A = \frac{0.02 \pm \sqrt{0.006^{2}-4\cdot (0.006)\cdot (- 9)}}{2\cdot (0.006)}$

A = 1.667 + 38.733

A = 40

By knowing the blood pressure and applying the quadratic formula, the age of a man whose normal blood pressure is 129 mm Hg is 40 years old.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

4 0

2 years ago