if a sum of money increased by 1/5 of itself every year and in 5 years amounts to Rs.8546,find the sum
1 answer:
Answer:
Answer :
Given : If a sum of money amounts to Rs 2200 in 5 years
Let sum of money = x
And as given : The interest is 3838 of the principal . So we get
x ( 3838 ) = 2200 - x
3x = 17600 - 8x
11x = 17600
x = 1600
So, Sum of money = Rs . 1600
Then interest = 2200 - 1600 = Rs . 600
Let Rate of interest = r %
And we know Simple interest = P × r × t100P × r × t100 , So we get
⇒1600 × r × 5100 = 600⇒16× r × 5100 = 6⇒80r = 600⇒r = 60080 = 152 = 712%⇒1600 × r × 5100 = 600⇒16× r × 5100 = 6⇒80r = 600⇒r = 60080 = 152 = 712%
So
Step-by-step explanation:
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Answer:
A) (17 ; 550)
B) $17/item
C) 550
Step-by-step explanation:
First we must calculate the intersection point of the two lines. Since in that point <em>y</em> has the same value in both equations, we can obtain <em>x </em>by equalling the two equations and then using that value for obtaining <em>y</em>:
So the value of <em>x</em> in the intersection point is 17. We now use this value with either one of the equations to obtain <em>y</em><em>. </em>Let's use the supply equation:
So the intersection point is (17 ; 550)
Supply and demand are in equilibrium when the amount of items on supply are the same as the ones on demand. That is the point were the two lines intersect, which means the selling price is the <em>x</em> coordinate and the amount of items is the <em>y</em> coordinate, so that is a selling price of <em>$17/item</em> with a number of items of <em>550</em>.